pos()

Syntax

pos(substring,string)

Description

Returns the position of substring in string, or zero if substring is not contained in string.

The substring must be contained within string in its entirety for the returned value to be non-zero. Also, the comparison is case sensitive and only the first occurrence of substring is returned (see third example).

Example

Calculate lResult as  pos('Mouse','Mickey Mouse')
# returns 8 

Calculate lResult as  pos('mouse','Mickey Mouse')
# return 0, note case 

Calculate lResult as  pos(' ','R S W Smith')
# returns 2, that is the position of the first space character 

# you can strip the extension from a filename using mid() and pos() combined 
If  pos('.',lFileName) ## if lFileName contains a dot
  Calculate lFileName as  mid(lFileName,1,pos('.',lFileName)-1)
End If